in square ABCD sod ebc|| side AD , side AB = side DC
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>>In ABCD, side BC side AD, side AB
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In □ABCD, side BC∥ side AD, side AB≅ side DC If ∠A=72
∘
then find the measure of ∠B, and ∠D
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side BC∥ side AD
Interior angles on the same side of the transversal are supplementary.
∠A+∠B=180
∘
⇒72
∘
+∠B=180
∘
⇒∠B=180
∘
−72
∘
⇒∠B=108
∘
Construction:
Draw BP ∥⊂D
So,BC∥AD and BP∥CD
⇒PBCD is a parallelogram
⇒CD≅BP
Now CD=BP and CD=AB
⇒BP=AB
⇒∠BAP=∠BPA=72
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BP∥CD so,
∠CDP=∠BPA=72
∘
(corresponding angles are equal)
∠B=108
∘
∠D=72
∘
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