Question

in square PQRS :
1) if PQ =3x-7 and QR=x+3, find PS
2) if PR=5x and QS=9x-8, find QS​

Answer 1

Answer:

Step-by-step explanation:

As it is a Square :

So,

*All the sides are equal ...

So,

3x-7=x+3

3x-x=7+3

2x=10

x=10/2

=>x = 5

Substituting:

x+3 = 5+3 = 8

PS = 8

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We know that the diagonals of a square are equal

Thus,  

PR = QS  

5x = 9x - 8

4x = 8

x = 2.

Now,

QS = 9x - 8 = 18 - 8 = 10.

Thus,  

QS = 10.

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Answer 2

3x-7=X+3

3x-x=3+7

2x=10

X=10/2

X=5

PS=5

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