In square PQRS : (i) if PQ = 3x – 7 and QR = x + 3 ; find PS
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PQ=QR (as sides are equal)
therefore
3x-7=x+3
3x-x=3+7
2x=10
x=10/2
x=5
PQ=3x-7
3×5-7
15-7
8=PQ
PQ=PS (as side are equal)
PS=8cm
therefore
3x-7=x+3
3x-x=3+7
2x=10
x=10/2
x=5
PQ=3x-7
3×5-7
15-7
8=PQ
PQ=PS (as side are equal)
PS=8cm
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