Math, asked by jayabiju101, 15 days ago

In square PQRS1.
If PQ = 3x-7 and QR=x+3 ,find PS2.
If PR=5x and QS= 9x-8,Find QS

Answers

Answered by MariyaManir
0

Answer:

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Answered by priyoshichoudhuri
0

Step-by-step explanation:

Correct option is C)

In square PQRSPQ=QR (Since all the sides of a square are equal)

⇒3x−7=x+3

⇒x=5

Hence putting the value of x we get

PQ=3(5)−7

Therefore, PQ=8 units

Hence PS=8 units (Since all the sides of a square are equal)

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