Question

In standstill water a steam boat is accelerated 3 m per square from position of rest in an interval of 8 sec determine the distance travel by the boat within the interval

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Answer 1

use the equation

$s = ut \: + \frac{1a {t}^{2} }{2 } \\ s = \: 0(8) + \frac{1(3)( {8}^{2} )}{2} \\ s = \frac{192}{2} \\ s = 96$

so the distance travelled by boat in 8 sec is 96 m

Answer 2

Answer:

$use the equation</p><p></p><p>\begin{gathered}s = ut \: + \frac{1a {t}^{2} }{2 } \\ s = \: 0(8) + \frac{1(3)( {8}^{2} )}{2} \\ s = \frac{192}{2} \\ s = 96 \\ \end{gathered}s=ut+21at2s=0(8)+21(3)(82)s=2192s=96</p><p></p><p>so the distance travelled by boat in 8 sec is 96 m</p><p></p><p>$

Step-by-step explanation:

hi piyush how are you