Chemistry, asked by panchalvaiahnav250, 4 months ago

in storng acid-strong base titration,the pH of mixture at initial stage find out by formula

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Answered by roychhaya63
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Answered by HanitaHImesh
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  • Let, N1 and V1 be the strength and volume of the strong acid .
          N2 and  V2 represents the same for a strong base.
  • N1V1 is the concentration of strong acid and N2V2 is the concentration of strong base

 1).  If, N2V2 > N1V1

    (solution is basic)

     \frac{N2V2 - N1V1}{V2+V1} = [OH⁻]

The required formulae for the pH of the mixture at the initial stage of  acid-base titration = [H⁺] = \frac{10^{-14} }{[O]}

pH = -log₁₀[H⁺]

2). If N1V1 > N2V2

     (solution is acidic)
     [H⁺] = \frac{N1V1 - N2V2}{V1+V2}

The required formulae for the pH of the mixture at the initial stage of  acid-base titration

     pH = -log₁₀[H⁺]


     

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