Question

In such numbers which are divisible by 5 and also those which have 5 as one of the digits are eliminated from the number 1 to 60,how many numbers would remain?

Answer 1

40 numbers would remain

the eleminated numbers are

5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60

Answer 2

Only 40 numbers would remain in the list.

1) Since, we have to delete all the numbers containing 5 we would delete 50-59 i.e 10 numbers.

2) The remaining numbers would be 1-49 and 60

3) Now the multiples of 5 would be 5,10,15,20,25,30,35,40,45,60 i.e 10 numbers

4) Deleting them from the list gives 60-10-10= 40 numbers in the list.