Chemistry, asked by anand6448, 11 months ago

In system A(s) = 2B(g) + 3C(g) at equilibrium
if concentration of 'C' is doubled then concentration
of B at equilibrium
(1) Double its original concentration
(2) Half its original concentration
(3) 272 its original concentration
(4),
its original concentration​

Answers

Answered by Anonymous
0

Explanation:

In system A(s) = 2B(g) + 3C(g) at equilibrium

if concentration of 'C' is doubled then concentration

of B at equilibrium

(1) Double its original concentration

(2) Half its original concentration

(3) 272 its original concentration✔️✔️

(4),

its original concentration

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