In system A(s) = 2B(g) + 3C(g) at equilibrium
if concentration of 'C' is doubled then concentration
of B at equilibrium
(1) Double its original concentration
(2) Half its original concentration
(3) 272 its original concentration
(4),
its original concentration
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Explanation:
In system A(s) = 2B(g) + 3C(g) at equilibrium
if concentration of 'C' is doubled then concentration
of B at equilibrium
(1) Double its original concentration
(2) Half its original concentration
(3) 272 its original concentration✔️✔️
(4),
its original concentration
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