Question

in system of two particle if only M2 is oscillating then its time period is​

Answer 1

Therefore Time Period of the system where only particle m₂ is oscillating is T = √m₂/√k.

Given:

The system with two particles ( m₁ and m₂ ) but only a second particle (  m₂ ) oscillates.

To Find:

The time period for the given system where only m₂ oscillates.

Solution:

We can simply solve this numerical problem by using the following process.

The angular frequency of a vibrating system is given by

⇒ ω = $\sqrt{k/m\\}$

where k = Stiffness of spring

m = Mass of the body attached

The time period of the system is given by

⇒ T = 1/ω

⇒ T = $\sqrt{m/k}$

When only m₂ is oscillating the Time period is given by

⇒ T = √m₂/√k

Therefore Time Period of the system where only particle m₂ is oscillating is T = √m₂/√k.

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