Question

In temperature scale X, water boils at -60X and freezes at-180X What would a temperature of 350 Kelvin be on this scale? i tried to solve it via unitary method (373K= -60X freezing points, 350K should be equal to -56X approx.) but its not -56X pl tell me where i did my mistake

Answer 1

Answer:

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Answer 2

Explanation:

We assume scale X is a linear scale in the sense that if its reading is x then it is related to a reading y on the Kelvin scale by a linear relationship y=mx+b. We determine the constant m and b by solving the simultaneously equations:

373.15=m(−53.5)+b

273.15=m(−170)+b

which yield the solution m=100/(170−53.5)=0.858 and b=417. Which these values, we find x for y=340:

x=

m

y−b

=

0.858

340−419

=−92.1

o

X