Question

In th figure angle BAD=3angleDBA,find Angle DBA,angle DBC and angle ABC​

Answer 1

Answer:

Step-by-step explanation:

In Δ ABD,

∠DAB + ∠DBA + ∠ADB = 180°

3x + x + 104° = 180° (Angle Sum Property)

or, 4x + 104° = 180°

or, 4x = (180-104)°

or, 4x = 76°

or, x = $\frac{76}{4}$

or, x = 19°

Therefore,

∠DBA = x = 19°

In Δ DBC,

∠DBC + ∠DCB = 104° (Exterior Angle Property)

∠DBC + 65° = 104°

∠DBC = (104 - 65)°

∠DBC = 39°

Therefore,

∠ABC = ∠DBA + ∠DBC

∠ABC = 19° + 39°

∠ABC = 58°

ANSWER: ∠DBA = 19°, ∠DBC = 39°, ∠ABC = 58°