In tha AD is the tangent line of the circle and ABC is the secant line. If AB =4cm and BC=5cm, then the length of AD is
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Hello Dear,
Your Answer is Here,
Refers to The Diagramatic Attachments for the question .
Given there,
AB = 4 cm
BC = 5 cm
AC = AB + BC
∴ AC = 9 cm
We know , If a chord in a Tangent Intersect externally , Then the product of the length of the segment of the chord is equal to the square of the length of the Tangent From the Point of Contact to the Point of Intersection.
Thus ,
AD² = AB × AC
AD² = 4 × 9
AD = √36
AD = 6 cm.
Thus , Length of the AD is 6 cm.
I hope it helps.
Have a Marvelous Day.
Your Answer is Here,
Refers to The Diagramatic Attachments for the question .
Given there,
AB = 4 cm
BC = 5 cm
AC = AB + BC
∴ AC = 9 cm
We know , If a chord in a Tangent Intersect externally , Then the product of the length of the segment of the chord is equal to the square of the length of the Tangent From the Point of Contact to the Point of Intersection.
Thus ,
AD² = AB × AC
AD² = 4 × 9
AD = √36
AD = 6 cm.
Thus , Length of the AD is 6 cm.
I hope it helps.
Have a Marvelous Day.
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