in that ques in last what I take common
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actually u had a mistake in this it will be like
6x^2+15x+2x+5=0
3x(2x+5)+1(2x+5)=0
(2x+5)(1+3x)=0
hope his helps u plz mark it as brianliest answer plz
6x^2+15x+2x+5=0
3x(2x+5)+1(2x+5)=0
(2x+5)(1+3x)=0
hope his helps u plz mark it as brianliest answer plz
Anonymous:
aapna ×( 6×+15 ) + in between number kasa put kra h ( 6x +15 )
please it urgently
6x5=30→15x2 so 17 can be written as 15&2 and then else is solved in answer
plz mark it as brianliest answer plz
I am asking in 2 nd method you put 1 how
from x(6x+15) we hav taken 3x common so what remains in bracket is 2x+15 and in second part we have 2x+5 so when we take 1 common so we get in bracket (2x+5)
plz mark it as brianliest answer
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u have done it wrongs it will be
3x (2x+5)+1 (2x+5)
(2x+5)(3x+1)
x=-5÷2 or x=-1÷3
x=-2.5 or x=-0.33
3x (2x+5)+1 (2x+5)
(2x+5)(3x+1)
x=-5÷2 or x=-1÷3
x=-2.5 or x=-0.33
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