Math, asked by Mihir1753, 9 months ago

In that same discussion, it was stated that for the ideal block cipher, which allows all possible reversible mappings, the size of the key is n * 2n bits. But, if there are 2n! Possible mappings, it should take log2 2n! Bits to discriminate among the different mappings, and so the key length should be log2 2n! . However, log2 2n! 6 n * 2n. Explain the discrepancy

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Answered by FeyisayoFijabi
0

Answer: Use Google

Step-by-step explanation:

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