Math, asked by Mihir1753, 10 months ago

In that same discussion, it was stated that for the ideal block cipher, which allows all possible reversible mappings, the size of the key is n * 2n bits. But, if there are 2n! Possible mappings, it should take log2 2n! Bits to discriminate among the different mappings, and so the key length should be log2 2n! . However, log2 2n! 6 n * 2n. Explain the discrepancy

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Answered by FeyisayoFijabi
0

Answer: Use Google

Step-by-step explanation:

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