Question

In the 1961-1962 NBA basketball season, Wilt Chamberlain of the Phildelphia Warriors made 30
baskets. Some of the baskets were free throws (worth 1 point each) and some were field goals (worth 2
points each). The number of field goals was 10 more than the number of free throws.
(a) How many field goals did he make?
(i) 10 goals (ii) 20 goals (iii) 15 goals (iv) 18 goals
(b) How many free throws did he make?
(i) 10 throws (ii)20 throws (ill) 15 throws (iv) 18 throws
(c) What is the total number of points scored?
(0) 50 (ii) 80 (ili) 60 (iv) 45
(d) If Wilt Chamberlain played 5 games during this season, what was the average number of points per
game?
(0) 5 (b) 8 (iii) 10 (iv) 4​

Answer 1

Answer:

i 20 goals

ii 10 goals

iii 50

iv 10

Answer 2

Answer:

(a) - option (ii) 20  field goals he make

(b) - option (i) 10 free throw goals he make

(c) - option (i) 50 is the total no. of points he scored

(d) - option (iii) 10 is the average no. of points per game  

Step-by-step explanation:

Explanation:

Given , Wilt Chamberlain of the Phildelphia  Warriors made 30 baskets .

Some of baskets were free throws goals (worth 1 point ) and

some of baskets were field goals  (worth2 points )

Total numbers of goals we have 30

Let x be the number of free throw goals

So, no. of field goals will be (30-x)

Step1:

We have also given that , the no. of filed goals was 10 more than the number of free throws .

Therefore , (x+10)       (x is the no. of free throw goals)

⇒(x+10) = (30 - x)

⇒2x = 20

⇒ x= 10

There fore , he make 10  free throw goal

and   2x = 2× 10 = 20  , he make 20 field goals

Step2:

Total no. of free throw goals and field throw goal we have 10 and 20 .

But given that for each free throw  goals he worth  1 point and

for filed goals he worth 2 points for each goals .

∴ points in free throw goals = 10 × 1 = 10 points

and no. of points  in field goals = 20 × 2= 40

So , the total no. of points = 10+ 40 = 50 points

Step3:

We have total numbers of points = 50

and Wilt Chamberlain played 5 games

So, the average number of points per game = $\frac{50}{5} = 10$

Final answer :

Hence , (a) there are 20 field goals he make ,

             (b) there are 10 no. of free throw goals

            (c) 50 points he scored.

            (d) the average no. of points per game is 10

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