Question

In the 5 digit no. 1b6a3, a is the greatest single digit perfect cube and twice of it exceeds b by 7. then sum of the no and its cube root is

Answer 1

Greatest single digit perfect cube = 8
a=8
b=2a-7=9
No. : 19683
Ans : 19683+(19683)^1/3 = 19683+27
= 19710

Answer 2

Greatest Cube root single digit=8
B=TWICE a exceeds it by 7
Means B=2a-7
=9
A=8
B=9

Number=19683
Its Cube root=27
Sum of number and cube root
19683+27
=19710