In the (a) AABC= given figure, ADBC AB = DC and LABC = ZDCB. Prove that (b) ZA = ZD (c) AAOB = ADOC (d) AOBC is isosceles.
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(a) AB = DC (given)
∠ABC = ∠DCB (given)
BC = BC (common)
Therefore ΔABC congruent to ΔDBC (SAS congruence)
(b) ∠A = ∠D (CPCT)
(c) ∠AOB = ∠DOC
∠A = ∠D
AB = DC
Therefore ΔAOB congruent to ΔDOC (AAS congruence)
(d) OB = OC (CPCT)
Therefore, ΔBOC is isosceles.
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