in the A.P=4,7,10.... if the last term is 100 then find the sum of all terms
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2
Answer:
LAST TERM 100
SO, A= 4 ; D = 7-4 ==> 3 ;
AP = A+(N-1)D
AP = 4+(100-1)3
AP = 4+(99)3
AP = 4 + 297
AP = 301
SUM OF 100 TERM = [A+AP]
SUM = [4+301]
SUM = 305
jaip3465:
no. of terms n is not given as 100,but the value of last term is given as 100
Answered by
3
Given ap=4,7,10
A=4
D=7-4=3
An=100
100=a+(n-1)d
100=4+3n-3
100+3-4=3n
99=3n
N=33
Sum of all terms
Sn=n/2(2a+(n-1)d)
Sn=33/2(2*4+32*3)
Sn=16.5(8+96)
Sn=16.5*104
Sn=1, 716
A=4
D=7-4=3
An=100
100=a+(n-1)d
100=4+3n-3
100+3-4=3n
99=3n
N=33
Sum of all terms
Sn=n/2(2a+(n-1)d)
Sn=33/2(2*4+32*3)
Sn=16.5(8+96)
Sn=16.5*104
Sn=1, 716
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