Question

In the AABC, angle B =90°, AB= 4 cm, BC= 3 cm, then
SinA=​

Answer 1

Step-by-step explanation:

given triangle is right angled triangle

follow pythagoras theorem

42+32=C2

by solving

you will get 3rd side

C=5

so we know that

sinA = perpendicular/Hypotenuse

=) given B=90° so in triangle side apposite to 90°is Hypotenuse and side having 99°is perpendicular

so,

SinA=AB/AC=4/5

=0.8

Answer 2

${ab}^{2} + {bc}^{2} = {ac}^{2}$(3)^2 + (4)^2= (ac)^29 + 16=(ac)^2(ac)^2=25ac=5