Question

In the AABC, DE || BC. If AB : AD = 5: 3 then area of AABC : area of AADE
is
A. 3:5
B. 6:10
C. 9:25
D. 25:9​

Answer 1

Step-by-step explanation:

by Thales theorem AB/AD-1= DB/AB=2/5

SO AD= 2

DB=3

AS AREA OF SIMILAR TRIANGLES IS

EQUAL TO THE SQUARE OF THE RATIO OF THEIR CORRESPONDING AREAS. SO RATIO WILL BE 25: 9

Answer is D) 25:9