In the ΔABC, AB=AC and AD ⊥ BC, prove that D is mid-point of BC.
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Answered by
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Step-by-step explanation:
We have,
InΔABC,AB=AC.and AD is the median.
Then prove that,
InΔABC,AD is the perpendicular bisector of BC.
Proof:-
In
ΔADBandΔADC
AB=AC(Giventhat)
AD=AD(Commonline)
∠ADB=∠ADC(Everyrightangle)
Then, ΔADB≅ΔADC by S.A.S. rule
So, AD is the perpendicular bisector of BC.
Hence proved.
Answered by
2
Hence, it is proved that D is mid point of BC.
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