In the ∆ abc if a b is greater side then prove that angle c is greater than 60 degree
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AB is greatest side
=)AB>BC
That is ,∠C > ∠A -----1)
=) AB > AC
That is, ∠C > ∠B-----2)
adding these eq. 1) and 2) we get ,
=)2∠C > ∠A + ∠B
=)3∠C > ∠A + ∠B + ∠C
=)3∠C > 180°
=)∠C > 60°
Hence, proved.
Hope it helps..
Mark as brainliest
AB is greatest side
=)AB>BC
That is ,∠C > ∠A -----1)
=) AB > AC
That is, ∠C > ∠B-----2)
adding these eq. 1) and 2) we get ,
=)2∠C > ∠A + ∠B
=)3∠C > ∠A + ∠B + ∠C
=)3∠C > 180°
=)∠C > 60°
Hence, proved.
Hope it helps..
Mark as brainliest
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