Question

in the above arrangement of two masses a and b the acceleration of the blocks is 6 metre per second square if the mass of the block A is 10 kg then the mass of block B is​

Answer 1

Answer:

As per constant relation if acceleration of block B is

′′

a

′′

then

acceleration of block A is "2a"

now as per force equation of B

m

b

gsin45−2T=m

b

a

T−m

a

gsin45=m

a

×2a

now solving above two equations for acceleration of the blocks

m

b

gsin45−2m

a

gsin45=(m

b

+4m

a

)×a

a=

m

b

+4m

a

(m

b

sin45−2m

a

sin45)g

now plug in all values

a=

40+40

(20

2

−10

2

)9.8

a=6.6m/s

2

So, acceleration of block B is 6.6m/s and acceleration of block A is 13.2m/s

2