Question

In the above, at what depth below
the surface o the earth the weigh
of the man wall be half of that on
the surface of Earth​

Answer 1

Answer:

Could you please provide a figure of your question

Answer 2

Answer:

Explanation:  This can be solved using the relation g'/g = 1-(2h/Re) where g'is the acceleration due to gravity at a height h. Re is the radius of earth and g is the value of acceleration due to gravity at earth's surface. on solving this we get h = 1600 km. This is the ht at which a man would weigh half as much as on earth.