Question

In the above circuit diagram, calculate:
(a) the value of current through each resistor.
(b) the total current in the circuit.
(c) the total effective resistance of the circuit.
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Answer 1

Explanation:

(i) Here R1= 5 ohm, R2= 10 ohm and R3= 30 ohm

The value of current through each resistor is different as they are arranged in parallel connection.

So the current through 5 ohm resistor, I1 = V/R = 6/5 = 1.2A

So the current through 10 ohm resistor, I2 = V/R = 6/10 = 0.6A

So the current through 30 ohm resistor, I3 = V/R = 6/30 = 0.2A

(ii) The total current in the circuit = I= I1+ I2+ I3

1.2A + 0.6A + 0.2A = 2A

(iii) Total resistance in the circuit = R, As the circuit is in parallel connection, so





R= 3 ohm

Answer 2

Answer:

Explanation:

(i) Here R1= 5 ohm, R2= 10 ohm and R3= 30 ohmThe value of current through each resistor is different as they are arranged in parallel connection.So the current through 5 ohm resistor, I1 = V/R = 6/5 = 1.2ASo the current through 10 ohm resistor, I2 = V/R = 6/10 = 0.6ASo the current through 30 ohm resistor, I3 = V/R = 6/30 = 0.2A

(ii) The total current in the circuit = I= I1+ I2+ I31.2A + 0.6A + 0.2A

R=3

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