Question

in the above diagram LINT is a rectangle, find the perimeter​

Answer 1

Given

LY = 5.2

YT = 3.9

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To Find

Perimeter of given rectangle.

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Solution

We will apply Pythagorean Theorem here because if we look closely we can see a right angled triangle formed in the rectangle.

Pythagorean Theorem ⇒ (Base)² + (Height)² = (Hypotenuse)²

Base ⇒ LY = 5.2

Height ⇒ YT = 3.9

Hypotenuse ⇒ LT = x

⇒ (5.2)² + (3.9)² = (x)²

⇒ 27.04 + 15.21 = x²

⇒ 42.25 = x²

⇒ x = √42.25

⇒ x = 6.5

∴ LT = 6.5

LT = IN (Opposite sides are equal)

Perimeter of Rectangle ⇒ 2 (Length + Breadth)

Length ⇒ 6.5

Breadth ⇒ y

Perimeter of Rectangle ⇒ 2 (6.5 + y)

Perimeter of Rectangle ⇒ 13 + 2y

∴ The perimeter of the given rectangle is 13 + 2y

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Answer 2

Question :

In the above diagram LINT is a rectangle, find the perimeter.

Given that :

• LY measures 5.2
• YT measures 3.9

To find :

• Perimeter of the rectangle.

Solution :

• Perimeter of the rectangle = 13+2c

Using concept :

• Phythagoras theorm.
• Perimeter of rectangle.

Using formula :

• Phythagoras theorm = (Hypotenuse)² = (Base)² + (Height)²
• Perimeter of rectangle = 2(l+b)

Know more :

We also write these as :

• Length as l.
• Breadth as B
• Perimeter as P
• Base as B.
• Height as H.

Perpendicular means Hypotenuse.

• Perpendicular as P

Assumption :

• Let a is Hypotenuse.
• Let c is breadth.

According to the question :

• Base = 5.2
• Height = 3.9

Understanding the concept :

• This question says that there is a rectangle given named LINT and Y is the centre point of this rectangle. This rectangle's angle measure like this = LY measure 5.2 and YT measures 3.9.

Note : We don't use any measurement here like cm etc coz it's not given in the question and we have to work according to the question always.

Procedure of this question :

• To solve this question we have to use the Phythagoras theorm. { Are you confused due to the using if phythagoras theorm because as we know that we use this theorm in some questions of right angled triangle } { Yes, we are confused } { No, need to worry let's see why we use this here } We use phythagoras theorm here because the rectangle is looking like a right angled traingle. That's why phythagoras theorm will be used here Now by using it's rule we have to put the values. Afterthat we have to use the formula to find the perimeter of rectangle. Afterwards we get our final result that is

Full solution :

Phythagoras theorm = (Hypotenuse)² = (Base)² + (Height)²

Here,

• Hypotenuse = a
• Base = 5.2
• Height = 3.9

Putting the values,

→ (5.2)² + (3.9)² = a²

→ 27.04 + 15.21 = a²

→ 42.25 = a²

→ a = √42.25

→ a = 6.5

(a as l = 6.5)

• LT = IN (Opposite sides are equal)

Perimeter of rectangle = 2(l+b)

→ Perimeter of rectangle = 2(6.5+c)

→ Perimeter of rectangle = 13 + 2c