Question

in the above example,assuming that the bench on which mahendra is sitting is frictionless,starting with zero velocity,What will be mahendra's velocity of motion towards virat after 1s ? will this velocity,change with time and how how to solve this numerical​

Answer 1

Answer:

Explanation:

Given:F = 4.002 X 10^-7 N,

m=75Kg.

Solution: According to Newton's 2nd law of motion,

F=ma

a=F/m

=4.002 X 10^-7/75

=4002 X 10^-10/75

=53.36 X 10^-10 (dividing 4002 by 75)

= 53.4 X 10^-10 (round up .36 as .4)

= 5.34 X 10^-9 m/s^2.

According to newton's 1st equation of motion,

V=U+at.

=0 + 5.34 X 10^-9 X 1

= 5.34 X 10^-9 m/s.

Answer 2

Explanation:

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