In the above fig,if AB||CD ,CD||EF and y:z=3:7, find x
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Answer:
x=126.........................
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as ABIICD and CDIIEF
thus,ABII EF
now, z=x ( alternate interior angles)-------(i)
let y=3t and z = 7t
then from (i) x=z= 7t-------(ii)
now as ABIICD
x+y =180⁰ (consecutive interior angles)
on putting the value of x&y from (ii) we get,
3t+7t=180⁰
10t=180⁰
t=180⁰/10
t=18
thus x=z=7t= 7×18= 126⁰
therefore, the value of x=126⁰ans
by the are you in class9
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