Question

In the above figure, A–O–B and Angle BOC = 3x°, Angle AOC = ( 3x+60°),the measure of Angle BOC is ?
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Answer 1

Step-by-step explanation:

Given: Angle BOC = 3x°, Angle AOC = ( 3x+60°).In question's figure.

To find: Measure of Angle BOC is ?

Solution:

Tip: Sum of angles on a straight line is 180°.

Here two angles are formed on line AB.

$\angle \: AOC + \angle \: BOC = 180° \\\\(3x+60)°+3x°=180°\\\\6x°=180°-60°\\\\6x°=120°\\\\x°=\frac{120°}{6}\\\\x°=20°$

Now,

Find angle BOC:

$\angle BOC= 3x°\\\\\angle BOC=3\times20°\\\\\angle BOC=60°$

Final answer:

$\angle BOC= 60°$

Hope it helps you.

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