Question

in the above figure
∠ABC = 69⁰ , ∠ACB = 31⁰ find
∠BDC​

Answer 1

Answer:

In △ABC

∠BAC+∠ABC+∠ACB=180

o

(Angle sum property)

∠BAC+69

o

+31

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=180

o

∠BAC=180

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−100

o

=80

o

For segment BADCB,

VBDC and ∠BAC are angles in the same segment. So, they must be equal

∴ ∠BDC=∠BAC (Angles in the same segment are equal)

∠BDC=80

o