Question

in the above figure, AC is the diameter and ABCD is the cyclic quadrilateral. angle EAB = 80 degree and Angle DCF = 110 degree, then find the angle made by AB at the centre of the circle

Answer 1

In the given figure,

ABCD is a cyclic quadrilateral

∠ADC=80° and ∠ACD=52°

Now, in cyclic quadrilateral ABCD

∠ABC+∠ADC=180

o

(Sum of opposite angles =180

o

)

⇒∠ABC+80

o

=180

o

⇒∠ABC=100

o

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