Question

In the above figure, Acceleration of bodies A, B and Care shown with directions. Values of b and c are w.r.t ground whereas a is acceleration of block A w.r.t Wedge C. Acceleration of block A w.r.t ground isIn the above figure, Acceleration of bodies A, B and Care shown with directions. Values of b and c are w.r.t ground whereas a is acceleration of block A w.r.t Wedge C. Acceleration of block A w.r.t ground is

a)​
$\sqrt{ {(b + c)}^{2} {a}^{2} }$
b)
$c - (b + a) \cos(θ)$
c)
$\sqrt{ {(b + c)}^{2} + {c}^{2} + 2(b + c) c\cos(θ) }$
d)
$\sqrt{ {(b + c)}^{2} + {c}^{2} + 2(b + c)c \cos(θ) }$

Step-by-Step explaination required.

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Answer 1

In the above figure, Acceleration of bodies A, B and Care shown with directions. Values of b and c are w.r.t ground whereas a is acceleration of block A w.r.t Wedge C. Acceleration of block A w.r.t ground isIn the above figure, Acceleration of bodies A, B and Care shown with directions. Values of b and c are w.r.t ground whereas a is acceleration of block A w.r.t Wedge C. Acceleration of block A

Explanation:

see the attachment

Answer 2

Answer:

$\textsf{(c).}\sqrt{(b + {c})^{2} + c^{2} - 2(b + c).c.cos \theta}$

Explanation:

$\textsf{a=b+c}$

$\textsf{net acceleration of}$

$A=\sqrt{a²+c²+2accos(π-\theta)}$

$=\sqrt{(b+c)²+c²-2(b+c).c.cos\theta}$

Report if it's wrong.