Question

In the above figure area of triangle ABF is 3 sq units, area of triangle AFE is 4 sq units and area of triangle BFD is 2 sq units. find the area of quadrilateral FECD​

Answer 1

Step-by-step explanation:

The area of the triangular region D can be represented by This is the rendered form of the equation. You can not edit this directly. Right click will give you the option to save the image, and in most browsers you can drag the image onto your desktop or another program. , where b is the base of the triangle (and is equal to the length of a side of the square region C) and h is the height of the triangle (and is equal to the length of a side of the square region B). The area of any square is equal to the length of a side squared. The Pythagorean theorem is used to find the length of a side of a right triangle, when the length of the other 2 sides of the triangle are known and is represented by This is the rendered form of the equation. You can not edit this directly. Right click will give you the option to save the image, and in most browsers you can drag the image onto your desktop or another program., where a and b are the lengths of the 2 perpendicular sides of the triangle and c is the length of the hypotenuse. Although completed calculations are provided in what follows, keep in mind that completed calculations are not needed to solve this problem.

If the area of B is 9, then the length of each side is 3. Therefore, h = 3. Then, b can be determined, since the area of the triangle is, by substitution, This is the rendered form of the equation. You can not edit this directly. Right click will give you the option to save the image, and in most browsers you can drag the image onto your desktop or another program. or 8 = 3b. Once b is known, the Pythagorean theorem can be used: This is the rendered form of the equation. You can not edit this directly. Right click will give you the option to save the image, and in most browsers you can drag the image onto your desktop or another program.. Thus, This is the rendered form of the equation. You can not edit this directly. Right click will give you the option to save the image, and in most browsers you can drag the image onto your desktop or another program.. The length of a side of A is thus This is the rendered form of the equation. You can not edit this directly. Right click will give you the option to save the image, and in most browsers you can drag the image onto your desktop or another program.; SUFFICIENT.

If the area of C is This is the rendered form of the equation. You can not edit this directly. Right click will give you the option to save the image, and in most browsers you can drag the image onto your desktop or another program., then the length of each side is This is the rendered form of the equation. You can not edit this directly. Right click will give you the option to save the image, and in most browsers you can drag the image onto your desktop or another program.. Therefore, This is the rendered form of the equation. You can not edit this directly. Right click will give you the option to save the image, and in most browsers you can drag the image onto your desktop or another program.. The area of the triangle is This is the rendered form of the equation. You can not edit this directly. Right click will give you the option to save the image, and in most browsers you can drag the image onto your desktop or another program. so This is the rendered form of the equation. You can not edit this directly. Right click will give you the option to save the image, and in most browsers you can drag the image onto your desktop or another program.; thus h = 3. Once h is known, the Pythagorean theorem can be used as above; SUFFICIENT. The correct answer is D; each statement alone is sufficient.

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