in the above figure if angle aob = 90 degree then the values of angles AOE,EOD and DOB are
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where os the figure bro
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Given : figure ∠COD=90 ° , ∠BOE=72° , and AOB is a straight line.
To Find : angles AOC , AOE, EOD and DOB
Solution:
3x & 72 forms a linear pair
=> 3x + 72° = 180°
=> 3x = 108°
=> x = 36°
x + 90 + y = 180°
=> x + y = 90°
=> 36° + y = 90°
=> y = 54°
∠AOE = 3x = 3 * 54° = 162°
∠EOD = y + 72° = 54° + 72° = 126°
∠DOB = y = 54°
∠AOC = x = 36°
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