In the above figure, if pairs of triangles are similar, then find the value of 'x'
Answers
Step-by-step explanation:
where is the figure please send it
In the above figure, if pairs of triangles are similar, then the value of 'x' are as follows:
Consider the attached figure while going through the following steps.
(i)
PQ/QR = TL/ST
5 / 3 = x / 4.5
x = 4.5 × 3/5
x = 7.5 cm
(ii)
AB/BC = PQ/QC
5 / (3+3) = x / 3
5 / 6 = x / 3
5 / 2 = x
x = 2.5 cm
(iii)
AB/BC = DE/CD
24 / 22 = 14 / x
x = 14 × 11 / 12
x = 12.8 cm
(iv)
RS/ST = RA/AB
(6+2) / x = 6 / 9
8 / x = 6 / 9
x = 8 × 9/6
x = 12 cm
(v)
PR/QR = PN/MN
(4+x) / 15 = 4 / 5
x = 4/5 × 15 - 4
x = 4 × 3 - 4
x = 8 cm
(vi)
XZ/YZ = XA/AB
(x+7.5) / 18 = x / 12
12 (x+7.5) = x × 18
12x + 90 = 18x
90 = 18x - 12x
90 = 6x
x = 15 cm
(vii)
ED/CD = AB/BC
x / 15 = 1.6 / 1.5
x = 15 × 1.6 / 1.5
x = 16 cm
(viii)
AC/BC = AE/BE
(5+4) / 6 = 5 / x
9 / 6 = 5 / x
x = 5 × 6 / 9
x = 3.33 cm
