Question

in the above figure QR upon QS =QT upon PR and angle 1 is = angle 2 show that triangle PQS~ triangle TQR
Ncert class 10
page 140
question-4​

Answer 1

it is solve by the cpct theorem

Answer 2

Answer:

Given

$\frac{qr}{qs} = \frac{qt}{pr}$

$< 1 = < 2$

TO PROVE

Triangle pqs= triangle tqr

Proof

$< 1 = < 2$

PR=QP (side opposite to equal angles are equal)

GIVEN

$\frac{qr}{qs} = \frac{qt}{pr}$

putting 1

$\frac{qr}{qs } = \frac{qt}{qp}$

Triangle pqs and triangle tqr

$< pqs = < tqr$

(Both angle common)

and.

$\frac{qr}{qs } = \frac{qt}{qp}$

(from (2)

hence triangle pqs ~tqr. (by side angle side criteria)

HENCE PROVED