Question

In the above figure , seg AB II side RO & seg AC ll side RS then prove that PB/PQ = PC/PS.

Please answer fast...​

Answer 1

In triangle PQR

by BPT

PB/BQ=PA/AR

ADDING 1 BOTH THE SIDE

ALSO CAN BE WRITTEN AS

PB/PQ=PA/PR............(1)

IN TRIANGLE PRS

PC/CS=PA/AR

ADDING 1 BOTH THE SIDES

ALSO CAN BE WRITTEN AS

PC/PS=PA/PR........(2)

FROM EQN (1) AND (2)

PB/PQ=PC/PS