Question

in the above figure the amount of heat required to convert 1g of ice at mius 20 into stream at 100 option a 729.6 cal option b 110.6 cal option c 180 Cal option d 539 Cal​

Answer 1

Explanation:

Amount of heat required = Change the temp Of Ice from -10 C to 0 C + Heat required to melt the Ice + Heat required to increase the temperature of water from 0 to 100 C + Heat required to convert water at 100 C to vapor at 100 C

=1×0.5[0−(−10)]+1×80+1×1×100+1×540

=5+80+100+540

=725cal