Question

In the above figure, the sides BC,CA and AB of a △ABC△ABChave been produced to D,E and F respectively. If ∠ACD=105∘∠ACD=105∘ and ∠EAF=45∘∠EAF=45∘, find angle A of △ABC△ABC.​

Answer 1

Answer:

given angle EAF = 45°

angle EAF + angle FAC = 180

° (sum of angles on a straight line)

so angle FAC = 135°

angle FAC + angle BAC = 180° (sum of angles on a straight line is 180°)

angle BAC = 45°

i.e., angle A is 45°