Physics, asked by utkarshsub4, 13 hours ago

In the above image, all three bulbs are identical and when all the tree bulbs glow, a current of 3A is recorded by the ammeter A. what happens to the glow of the other two bulbs when the bulbs B1 gets fused?​

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Answered by pranilyankanchi
0

Answer:

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Class 10th

NCERT - Science Exemplar

12. Electricity

Answer

(i) There will be no effect on glow of other two bulbs and will remain same when B1 gets fused because glowing of bulb depends on power and the potential difference and resistance remains same of other two bulbs.

(ii) When there are parallel connections:

Net resistance will be 1/R = 1/R1+1/R2+1/R3

Since resistance is same so, R’ = R/3

Applying ohm’s law V= IR

R =4.5Ω

Since B2 gets fused, so now only two bulbs B1 and B3 are in parallel

Therefore net resistance in parallel 1/R’ =2/R

R’ = 4.5/2 Ω

I = V/R’ = 2×4.5/4.5

I = 2A

So, current will be distributed in both the bulbs as 1 A each.

(iii) Power dissipated when all three bulbs glow together

P = V × I

P= 4.5 × 3 = 13.5 w

Answered by barkulgargi8
0

Answer:

not got sorry I will ask to father

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