Question

In the above problem velocity of the particle in the beginning of 5th second is

Answer 1

Answer:

A: There ARE people who can correctly formulate an equation for partial time of flight distance - but I am not one of them.

So I rely on a pedestrian method that does not conceal any pratfalls. Here it is:

Distance after five seconds:

s = u*t + 1/2* a* t^2

s = 10*5 +0.5*4*5^2 = 100 meters

Distance after four seconds:

s = 10*4 +0. 5*4*4^2 =72 meters

Distance DURING the fifth second = 100 - 72 =28 meters.