Question

In the above question 18, if internal bisector of angle B and angle C intersect

at P. prove that angle PBO=90° and angle BOC+ angle BPC = 180°​

Answer 1

Answer:

60°

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Answer 2

$789 + 456 - 123 \times 0 \div 7896541230 = 789651231524555568626418796889641230$

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