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hi friend
here's your answer looking for
to construct the equilateral triangle of each side having 6.5 CM follow the following steps:-
=> Step-1. with the radius of 6.5 CM make the circle from centre O.
=> Step-2. now make a radius OA.
=> Step-3. again take the distance of 6.5 CM and draw the arc from centre A.
=> Step-4. name the point of intersection as B.
=> Step-5. now join OB and OA.
hence, OAB is your required equilateral triangle that has each side 6.5 CM.
I had attached the image to the answer.
hope you are satisfied with my answer.
here's your answer looking for
to construct the equilateral triangle of each side having 6.5 CM follow the following steps:-
=> Step-1. with the radius of 6.5 CM make the circle from centre O.
=> Step-2. now make a radius OA.
=> Step-3. again take the distance of 6.5 CM and draw the arc from centre A.
=> Step-4. name the point of intersection as B.
=> Step-5. now join OB and OA.
hence, OAB is your required equilateral triangle that has each side 6.5 CM.
I had attached the image to the answer.
hope you are satisfied with my answer.
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