Question

In the above question , calculate i distance travelled from O to A ii distance travelled from B to C iii total distance travelled by the body in 16 second.​

Answer 1

Answer:

A)12m

B)18m

C)66m

Explanation:

(i) Distance travelled from O to

(i) Distance travelled from O to Area of ∆ OAE=½(OE)×EA

(i) Distance travelled from O to Area of ∆ OAE=½(OE)×EA=½×4×6

=12

=12 (ii) Distance travelled from

=12 (ii) Distance travelled fromC= Area of ∆ BCD

=12 (ii) Distance travelled fromC= Area of ∆ BCD=½× DC×DB

=12 (ii) Distance travelled fromC= Area of ∆ BCD=½× DC×DB=½(16-10)6

=12 (ii) Distance travelled fromC= Area of ∆ BCD=½× DC×DB=½(16-10)6=18m

=12 (ii) Distance travelled fromC= Area of ∆ BCD=½× DC×DB=½(16-10)6=18m(iii) We have already calculated in the distance travelled by the body from B

=12 (ii) Distance travelled fromC= Area of ∆ BCD=½× DC×DB=½(16-10)6=18m(iii) We have already calculated in the distance travelled by the body from B B=36cm

=12 (ii) Distance travelled fromC= Area of ∆ BCD=½× DC×DB=½(16-10)6=18m(iii) We have already calculated in the distance travelled by the body from B B=36cmThus , total distance travelled by the body in 16

=12 (ii) Distance travelled fromC= Area of ∆ BCD=½× DC×DB=½(16-10)6=18m(iii) We have already calculated in the distance travelled by the body from B B=36cmThus , total distance travelled by the body in 16second:-

=12 (ii) Distance travelled fromC= Area of ∆ BCD=½× DC×DB=½(16-10)6=18m(iii) We have already calculated in the distance travelled by the body from B B=36cmThus , total distance travelled by the body in 16second:-12+18+36=66

Answer 2

Explanation:

The correct Answer is (i) 12m ; (ii) 18m ; (iii) 66m

Solution

In Fig., (i) Distance travelled from O to A=area ofΔOAE=12(OE)×EA=12×4×6=12m

(ii) Distance travelled from B to C=area ofΔBCD

=12DC×DB=12(16−10)6=18m

(iii) We have already calculated in Q.3, the distance travelled by the body from A to B=36m.

Thus , total distance travelled by the body in 16 second =12+18+36=66m