Question

In the above question, calculate (i) distance travelled from O to A (ii) distance travelled from B to C. (iii) total distance travelled by the body in 16 sec.​

Answer 1

Answer:

Answers are with explanation are given below

Step-by-step explanation:

Please clear the points which one is O, A, B and C

(i) For OA, OA is hypotenuse of right angled triangle whose base = 4 unit and perpendicular = 6 unit

OA = $\sqrt{4^{2}+6^{2} }$

OA = 10 m

(ii) For BC, The distance travelled from B to C with a constant speed of 6 m/s for 6 seconds

BC = speed * time = 6*6 = 36 m

(iii) For distance travelled in 16 s,

Distance travelled from B to C =

$\sqrt{6^{2}+6^{2}} \\\sqrt{72}\\6\sqrt{2}$

Distance travelled in 16s = (10 + 36 + 6$\sqrt{2}$)m

= (46 + 6$\sqrt{2}$)m