Question

In the absence of catasyst ammonia burns in an excess of oxygen to produce steam and nitrogen. What is the volume of oxygen remaining when 60cm3 of ammonia burns in 100cm3 of oxygen all volumes being measured at the same temperature and pressure
35cm3
40cm3
45cm3
55cm3​

Answer 1

Answer:

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Answer 2

Answer:

55$cm^{3}$ oxygen will be left.

Explanation:

The balanced chemical equation is :

$4NH_{3} + 3O_{2} --> 6H_{2}O + 2N_{2}$

According to Gay Lussac's law,

4 volumes of $NH_{3}$ requires 3 volumes of $O_{2}$

Therefore,

60 volumes of $NH_{3}$ will require 45(=60*3/4) voles of $O_{2}$

Volume Oxygen left = 100 - 45 = 55 $cm^{3}$