In the absence of wind, rain is falling vertically with speed of 4m/s. After some time, wind starts blowing with 3m/s speed in North to south direction. Find the angle with the vertical that a man standing on horizontal ground must hold his umbrella to keep himself dry.
Answers
Answer:
tan ⁻1 (3/4)
Explanation:
Given In the absence of wind, rain is falling vertically with a speed of 4 m/s. After some time, wind starts blowing with 3 m/s speed in North to south direction. Find the angle with the vertical that a man standing on horizontal ground must hold his umbrella to keep himself dry.
Let OP = Vr and PQ = Vm be the velocities of rain and man.
Given Vr = 4 m/s vertically downwards from west to East direction.
Vm = 3 m/s from north to south, to protect himself from rain, the relative velocity is Vrm = Vr - Vm, So PQ¹ = - Vm
Now resultant vector is OQ
So tanθ = PQ¹ / OP
= Vm /Vr
= 3/4
Now tanθ = 3/4
θ = tan⁺¹ (3/4)
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Answer:
37 degrees
Explanation:
Vr = 3 m/s (on y axis)
Vm = 4m/s (on x axis)
Tan theta = y/x
= 4/3
theta = 37 degrees