Question

In the addjoining figure ∆Abc is an issoscels triangle in which AB = AC If BM PARELLEL TO AC AND CN PARELLEL TO AB PROVE THAT
1) ∆ BMC ~= ∆ CNB
(2) BM = CN
(HINT AB = AC = ANGLE ABC = ANGLE ABC)​

Answer 1

Answer:

To prove:- ∆BMC≈∆CNB

Solution:-

1)

BC=BC (common side) (S)

Also If AB=AC

then

∠B=∠C (If two opposite sides of a triangle are equal then their opposite angles are also equal) (A)

∠BMC=∠CNB=90° (given both perpendicular) (A)

So,by A.A.S congruence

∆BMC≈∆CNB

2)

To prove BM=CN

BM=CN (by C.P.C.T from the congruent triangles)

(Corresponding parts of congruent triangle)

hope it helps

Answer 2

Answer:

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Step-by-step explanation:

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