In the adj. fig. ab parallel to cd.find X and y.
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2y-10=2x+10(alt.int.angles)
2y-2x=10+10
2(y-x)=20
y-x=20/2
y-x=10
y=10+x
Now,
Let the angle beside (x-5) be a
a= x+y+15(alt. int. angles)
Again,
(2x+10)+(x-5)+(x+y+15)=180. (Linear
pair )
4x+20=180
4(x+5)=180
x+5=45
x=40°
Since, y=10+x
So, y=10+40
y=50°
So x=40°
y=50°
2y-2x=10+10
2(y-x)=20
y-x=20/2
y-x=10
y=10+x
Now,
Let the angle beside (x-5) be a
a= x+y+15(alt. int. angles)
Again,
(2x+10)+(x-5)+(x+y+15)=180. (Linear
pair )
4x+20=180
4(x+5)=180
x+5=45
x=40°
Since, y=10+x
So, y=10+40
y=50°
So x=40°
y=50°
Rainaebad:
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