Question

in the adjacent diagram calculate the potential difference across 8ohm resistor​

Answer 1

Answer:

2.857 V

Explanation:

In series equivalent resistance (R) is given by the formula

R = R1 + R2

R = 8 + 6

R = 14 ohm

From ohm's law

V = IR

$\frac{V}{R}$  = I

$\frac{5}{14}$ = I

Now to calculate p.d across 8 ohm resistor

V = IR

V = (8) x $\frac{5}{14}$

V = $\frac{40}{14}$

V = 2.857 V